Question

a) Find the values of ‘’ such that quadratic equation ( + 9) 2 + ( + 1) + 1 = 0 has no real roots?​

Answer 1

Answer:

  k>6 or k<−6

Step-by-step explanation:

⇒  The given quadratic equation is x2−kx+9=0, comparing it with ax2+bx+c=0

∴  We get, a=1b=−k,c=9

⇒  It is given that roots are real and distinct.

∴  b2−4ac>0

⇒  (−k)2−4(1)(9)>0

⇒  k2−36>0

⇒  k2>36

⇒  k>6 or k<−6

Answer 2

Step-by-step explanation:

I hope you are understand well.