Question

a. Find the volume of 1 g of H2gas in litres at N.T.P b.Find the volume of 20g H2at NTP.
c.What is the volume occupied by 6.022×1023 molecules of any gas at NTP?​

Answer 1

Answer:

Chemistry

Explanation:

a)

• Volumee of 1 mole of H2 gas is 22.4 Litres at NTP.
• (1 mole of H2 gas is 2 grams ).
• So Volume of 1 gram equivalent of H2 gas at NTP =22.4/2=11.2 Litres.

b)

• No. of molecules in H2 = 20/2 = 10
• Volume of any ideal gas at NTP = no. of molecules × 22.4 L
• = 10 × 22.4
• = 224 L

c)

• 6.022 × 10^23 molecules are contained in 1 mole, and 1 mole, of any gas at NTP occupies a volume of 22.4 litres.