a) Find the zeroes of x2
– x – 12 graphically.
(OR)
b) Find the zeroes of x2
– 6x + 9 graphically.
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Answer:
y= x^2-x-12
Using Graphical method we see that when,
x=1,y= -11
x=2,y= -10
x=4, y=0
x= -1, y= -10
x= -3 , y=0
Then, we see that -3 and 4 are the zeroes of the polynomial
Use the same formula for the second question
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