Question

a. Find two numbers whose sum is 48 and difference is 10?
b. The sum of two numbers is 34 and their difference is 8 which are the numbers ?​

Answer 1

Answer:

345

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Answer 2

Answers

(a) Let the sum of x + y = 48 (Equation 1)

and, the difference x - y = 10 (Equation 2)

Firstly, let me take the value of Equation 2 as x

∴ x = 10 + y

Now, writing the first Equation

x + y = 48

We have the value of x i.e 10 + y

∴ Subsisting Values

⟹ 10 + y + y = 48

⟹ 10 + 2y = 48

⟹ 2y = 48 - 10

⟹ 2y = 38

⟹ y = 19

Now, let's substitute Equation 1

⟹ x + y = 48

⟹ x + 19 = 48

⟹ x = 48 - 19

⟹ x = 29

Thus, Proved also

x + y = 48

⟹ 29 + 19 = 48

x - y = 10

⟹ 29 - 19 = 10

(b) Let the sum of x + y = 34 (Equation 1)

and, the difference x - y = 8 (Equation 2)

Firstly, let me take the value of Equation 2 as x

∴ x = 8 + y

Now, writing the first Equation

x + y = 34

We have the value of x i.e 8 + y

∴ Subsisting Values

⟹ 8 + y + y = 34

⟹ 8 + 2y = 34

⟹ 2y = 34 - 8

⟹ 2y = 26

⟹ y = 13

Now, let's substitute Equation 1

⟹ x + y = 34

⟹ x + 13 = 34

⟹ x = 34 - 13

⟹ x = 21

Thus, Proved also

x + y = 34

⟹ 21 + 13 = 34

x - y = 10

⟹ 21 - 13 = 8