A fire extinguisher delivers 2.2 Kg of CO2. The volume of CO2 at r.t.p. is
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Molar mass CO2 = 44g/mol
2200 g CO2 = 2200/44 = 50mol CO2
At rtp , 1 mol gas = 24.5L
50 mol gas = 50*24.5 = 1225L
Allowing for significant figures - volume = 1200L - Choice C is correct.
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