Question

A fireman, 59.8 m away from a burning building, directs a stream of water from a ground level fire hose at an angle of 44.5◦ above the horizontal. If the speed of the stream as it leaves the

hose is 45 m/s, at what height will the stream

of water strike the building? The acceleration

due to gravity is 9.8 m/s ^2.

Answer in units of m.

Answer 1

Explanation:

get the components

45sin44.5 ( vertically)

45cos44.5( horizontally)

Then use this equation to find time using range as the distance

$s = ut + \frac{1}{2} a {t}^{2} \\ horizontl \: accelertion \: is \: zero \\ 59.8 = 45 \cos(44.5) \times t \\ t = 0.93$

u - initial velocity

t - time

a- acceleration

s-distance

then again use the same equation to find the height

$s = ut + \frac{1}{2} a {t}^{2} \\ h = 45 \sin(44.5) + \frac{1}{2} \times 9.8 \times {0.93}^{2} \\ 35.77m$