Question

A fireman of mass 60 kg slides down a pole. He is pressing the pole with a force of 600 N. The coefficient of friction between the hands and the pole is 0.5, with what acceleration will the fireman slide down (g = 10 m/s2) = А 1 m/s2 B 2.5 m/s2 C 10 m/s2 D 5 m/s2​

Answer 1

Answer:

Given: a fireman of mass 60 kg slides down a pole. He is pressing the pole with a force of 600 N. The coefficient of friction between the hands and the pole is 0.5

To find with what acceleration will the fireman slide down

Solution:

Here mass, m=60kg

and coefficient of friction, μ=0.5=

2

1

and g=10m/s

2

Force applied by fireman, F=600N

Friction Force, f=μmg=

2

1

×60×10=300N

Net movement force,

F−f=ma

⟹600−300=ma

⟹a=

60

300

⟹a=5m/s

2

Hence the acceleration with which the fireman slide down is 5m/s

2

Answer 2

Answer:

here is your answer

Explanation:

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