Question

A fireman of mass 60 kg slides down a pole with force 600n frictionncoefficient is 0.5 find accelerarion

Answer 1

F=600N

μ=0.5

μ=f/N

f=300N

ΔF=F-f

ΔF=600-300

ΔF=300N

ΔF=m*a

300=60*a

a=5m/s²

Answer 2

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