Question

A fireman of mass 80 kg slides down a pole during a rescue mission. The force of friction is constant at 720 N. Find the acceleration of the man. (g =10)​

Answer 1

Answer:

a = 9 m/$s^{-2}$

Explanation:

mass = 80 kg

force = 720 N

acceleration = ?

W.K.T., F=ma

Substitute the values,

720 = 80*a

720/80 = a

a = 9 m/$s^{-2}$