Question

A fireman of mass 80 kg slides down a pole during a rescue mission. The force of friction is constant at 720 N. Find the acceleration of the man.

Answer 1

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Answer 2

Answer: 1 m/s^2

Explanation:weight=mg

• m=80 kg,g=10 m/s^2

• weight=80*10=800 N

• F=800-720 =80 N

We have,

• F=ma

• a=F/m

• a=80/80

• a=1 m/s^2