Math, asked by varunvkgarg, 9 months ago

A fires 5 shots to B’s 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 27 times, A has killed: a) 10 b) 25 c) 30 d) 17

Answers

Answered by hansika5040
1

option b

Hope this is helpful

Answered by Anonymous
4

A fires 5 shots to B's 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 27 times, A has killed: [A]. = 144.

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