Question

A fires 5 shots to B's 3 but A kills only once in 3 shots while B kills
once in 2 shots. When B has missed 27 times, A has killed:

Answer 1

B missed 27 times, this means B has fired 2(27)=54 shots. As B fires 3 shots A fires 5. Then, for 54 shots from B, A fires 54(5/3)=90. A kills once in 3 shots then for 90 shots, A kills 90/3=30. Answer: 30

Answer 2

Answer:30shots

Step-by-step explanation:B has missed 27 times, this means that B has fired 2*27=54 shots. As B fires 3 shots A fires 5 shots. Therefore when 54 shots are fired from B, A fires 54(5/3)=90. A kills once in 3 shots then for 90 shots, A kills 90/3=30.