A fires 5 shots to B's 3 but A kills only once in 3 shots while B kills
once in 2 shots. When B has missed 27 times, A has killed:
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B missed 27 times, this means B has fired 2(27)=54 shots. As B fires 3 shots A fires 5. Then, for 54 shots from B, A fires 54(5/3)=90. A kills once in 3 shots then for 90 shots, A kills 90/3=30.
Answer: 30
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Answer:30shots
Step-by-step explanation:B has missed 27 times, this means that B has fired 2*27=54 shots. As B fires 3 shots A fires 5 shots. Therefore when 54 shots are fired from B, A fires 54(5/3)=90. A kills once in 3 shots then for 90 shots, A kills 90/3=30.
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