Science, asked by edwerd675, 8 months ago

. A firetruck travelling at a speed of 30.0 m/s encounters an emergency and comes to a complete stop. How much time will it take for the car to stop if it decelerates at -4.0 m/s^2?

Answers

Answered by jijisiju2009
0

Explanation:

V = Vo + at

0 m/s = 30 m/s + (-4.0 m/s2) (t)

-30 m/s = (-4.0 m/s2) (t)

(-30 m/s) / (-4.0 m/s2) = t

t = 7.5 s

The (-) sign is for magnitude, speeding up or slowing down.

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