Question

A firework shell is accilerated from rest to a velocity of 50m/s over a distance of 0.250m calculate the acceleration and time

Answer 1

a = v² - u² / (2S)
a = 50² / (2*0.250)
a = 5000 m/s²

v = u + at
u = 0
t = v/a
t = 50 / 5000
t = 0.01 second

Answer 2

Applying the third kinematic equation ,

v^2 = u^2 + 2as
2500 = 2 x 0.250 x a
2500 ÷ 0.5 = a
a = 5000 m/s^2

Now, applying 1st kinematic equation,
v = u + at
50 = 5000t
t = 1/100 = 0.01 s

So the required answer is 5000 m/s^2 and 0.01 s

Hope This Helps You!