A fireworks Shell is accelerated from rest to a velocity of 50 m/s over a distance of 0.250 m. Calculate the acceleration. How long did the acceleration last ?
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WE KNOW THAT THIRD EQUATION SAYS THAT - v² - u² = 2*a*s
v =50 m/s
u = 0
s = 0.250 m
THEREFORE ,
50² - 0² = 2*a*0.250
a = 2500 / 0.250
= 5000 m/s²
WE KNOW THE FIRST EQUATION SAYS THAT - v = u + a * t
v = 50 m/s
u = 0
a = 5000 m/s²
THEREFORE ,
50 = 0 + 5000 * t
t = 50 / 5000
t = 0.01 s
BRAINLIEST PLSEASEEEEEEEE
v =50 m/s
u = 0
s = 0.250 m
THEREFORE ,
50² - 0² = 2*a*0.250
a = 2500 / 0.250
= 5000 m/s²
WE KNOW THE FIRST EQUATION SAYS THAT - v = u + a * t
v = 50 m/s
u = 0
a = 5000 m/s²
THEREFORE ,
50 = 0 + 5000 * t
t = 50 / 5000
t = 0.01 s
BRAINLIEST PLSEASEEEEEEEE
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