Question

A firm wants to randomly select 3 employees form a total of 10 employees. How many combination of 3 employees can be selected?

Answer 1

Answer:

120 combinations

Step-by-step explanation:

Total number of employees = n = 10

We have to select randomly = r = 3

Then

We know that

Total number of combinations = nCr

                                                   = 10C3

                                                   = 10! / (10-3)!×3!    

                                                   = ( 10×9×8×7! ) / 7! × 6

                                                   = 120    

So there are 120 way to combine the employees to select.