A first orden reaction takes 69.3 min for 50% completion. How much time will be needed for 80% Completion .
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Answer:
t
1/2
=69.3 min=
K
ln 2
K=
69.3
ln 2
min
−1
For 80% conversion, if we assume initial concentration
to be a
o
, concentration left would be
5
a
o
t×
69.3
ln 2
=ln(
a
o
/5
a
o
)
t=
ln 2
69.3 ln 5
=161 min
−1
Explanation:
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