Question

A first order gas phase reaction has an energy of activation of 240KJmol if the frequency factor of the reaction is 1.6×10^13/s calculate it's rate constant at 600K

Answer 1

Answer:

Explanation:

The formula,

Ki = A * e^-E/RT is used for the analyses,

Here we have the value of the frequency factor and temperature that is 240 kJ/mol at 600K temperature.

Also, the activation number if given to us. Hence, we can calculate Ki that is the rate constant of the reaction.

Answer 2

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Given:

A first order gas phase reaction has an energy of activation of 240 KJ mol.

if the frequency factor of the reaction is 1.6×10^13/s calculate it's rate constant at 600K.

Answer:

Using the formula:

$\sf = Ki = a \times E {}^{ \frac{E}{RT} } \\ \sf = \frac{240 \: KJ}{mol \: of \: 600 \: K}$

According to question we can the value and the value of the number ,

Hence, Ki = rate of the constant of reaction.