Question

A first order reaction completes 30% of the reaction in 40 minutes.Then what is the half life

Answer 1

Answer:

For a first order reaction,

t = 2.303/k Log [R]º / [R]

k = 2.303/40min Log100/(100-30)

= 2.303/40min Log 10/7

= 8.918 x 10-3 min-1

Therefore, t1/2 of the decomposition reaction is

t1/2 = 0.693/k

= 0.693 / 8.918 x 10-3 min

= 77.7 min (Approx)

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Answer 2

Explanation:

Refer the above attachment