Question

a first order reaction has a rate constant 1.15*10^-3.how long will 5g of this reactant take to reduce to 3g ?.
PLEASE VERY URGENT

Answer 1

given = initial quantity =(r)○=5g and final quantity =(r)=3g rate consta =1.15×10-3=5-1. formula of 1st order reaction k=2.303/1.15×10-3log(5,3) value of log 5/3=log.5_log3 = 0.2219=2.303/1.15×10_3×0.2219
after calculated we get
445sec
hence it will take 444 sec towards 5g of their reactants
I hope this answer is right

Answer 2

It will take 444 seconds for 5g of this reactant take to reduce to 3g

Explanation:

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant  =$1.15\times 10^{-3}s^{-1}$

t = time for decomposition

a = initial amount of the reactant  = 5 g

a - x = amount left after decay process = 3 g  

Putting in the values we get:

$t=\frac{2.303}{1.15\times 10^{-3}}\log\frac{5}{3}$

$t=444s$

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