Question

A first order reaction has a rate constant k = 5.5 × 10⁻¹⁴ S⁻¹. Find the half-life for this reaction.

Answer 1

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Solution : Given,

Rate constant = 5.5 × 10⁻¹⁴ S⁻¹.

Relation between the rate constant and the half life of the reaction is,
t1/2 = 0.693/k


where,

t1/2 = half life of the reaction

k = rate constant of the reaction

Now put all the given values in the above relation, we get

t1/2 = 0.693 / 5.5 × 10⁻¹⁴


t1/2 = 1.26X 10¹³ s

Therefore, the half life of the reaction is,
=1.26X 10¹³ s

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