A first order reaction has a rate constant of 10^-3 per seond.how much time will it take for 10g of the reactant to reduce 2.5 g
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Answer:
Explanation:
We know that for a first order reaction
t=2.303klog.aa−x
Here, initial concentration a=10g and concentration left after time ts=2.5g
i.e., (a−x)=2.5g,
Specific reaction conctant k=10−3s−1
∴ Time required for the reactant to reduce to 2.5g
=2.30310−3×log4=2.30310−3×0.6021 (Given log4=0.6021)
=1386.6s
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0
Answer:
1386.6s.............
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