Question

A first order reaction has specific rate constant of 10's! Calculate the time taken for 10gms to reduce to half the quantity...anyone ?​

Answer 1

Answer:

k=

t

2.303

log

[A

t

]

[A

0

]

t=

10

−3

2.303

log

2.5

10

t=2303×0.301×2=1386s.

Answer 2

Answer:

Specific reaction constant k = 10–3 sec–1. ∴ Time required for the reactant to reduce to equals space fraction numerator 2.303 over ...