a first order reaction is 15% complete in 20 minutes.how long Will it take to complete 60%?
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T=2.303/k*log intial percentage/left over percentage
Explanation:
So from this equation we made two eqations that is
20=2.303/klog100/85....1
t=2.303/k*log100/40....2
Now dividing eqation 1 by 2
20/t=log40/log85
20/t=0.32
=62
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