Question

A first order reaction is 50% completed in 2 5min.Cal time for 80% completion of the reaction

Answer 1

Answer : The time for 80% completion reaction will be, 58 minutes.

Solution :

As we know that the radioactive decay follow the first order kinetics

N = amount left after decay process = 100 - 80 = 20

= initial amount = 100

t = time for 80% completion reaction​ = ?

= half life = 25 minutes

Now put all the given values in this formula, we get the time for 80% completion reaction.

Therefore, the time for 80% completion reaction will be, 58 minutes.

Answer 2

Answer:

Explanation:

Half life of a first order reaction=0.693/k, where k is the rate constant of reaction.So,rate constant=0.693/25 min^{-1}

Time for particular completion of first order reaction t=

2.303/k * log(Ao/A),where Ao is the initial concentration,A is the concentration left after time tPutting values,time required=58.07min