A first order reaction is 75% complete in 32 minutes, then in how much time 50% of the action will be completed
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Answer:
K= 0.00072 T = 978 secs
Explanation:
We know the formula
K=2.303/T log R initial/R final
T=32 mins X 60 = 1920 sec
R initial= 100
R final= 100-75 =25
log R initial/R final = log 4
K = 0.00072
And now for 50%
T=2.303/K log R initial/R final
log R initial/R final = 100/50 = log2
T=978seconds
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