A first order reaction is 75% completed in 60 min,
then what will be rate of reaction if concentration of
reactant is 0.3 M?
A
6.93 x 10-1 M min-1
B
6.93 x 10-3 M min-1
C
0.693 M min-1
D
1.8 M min-1
Answers
Answer:
Write the rate of reaction in terms of the rate of disappearance of reactant and the rate of formation of products:
NO(g)+O3(g)→NO2(g)+O2(g)
2C2H6(g)+7O2(g)→4CO2(g)+6H2O(aq)
H2(g)+I2(g)→2HI(g)
4OH(g)+H2S(g)→SO2(g)+2H2O(aq)+H2(g)
Answer:
t1/2 = 30 min
Explanation:
Reactant attention isn't always uniform interior a catalyst particle. The reactant attention is maximum on the outside floor and lowest on the center, forming a decaying profile from the outdoor to the interior. Product attention has a reversed distribution.
In general, growing the attention of a reactant in solution, growing the floor location of a strong reactant, and growing the temperature of the response machine will all boom the charge of a response. A response also can be accelerated through including a catalyst to the response mixture.
a=100
x=75
a-x=100-5=25
t=2.303/k log a / a-x
60 min = 2.303/ok log 100/25
t1/2 = 30 min
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