Question

A first-order reaction is completed 20% in 10 minutes calculate the rate constant

Answer 1

answer for this question is 0.002303

Answer 2

Answer:

0.0223 min^ -1

Explanation:

Given that 20% reaction completed in 10 min

We known that time period for 1 St order reactions is

T = -2.303 log(final concentration/initial concentration)/k

For given reaction we need to find k

Now ,

initial concentration A = 100

Final concentration B = 80

And time T = 10 min

So ,

k = -2.303 log (B/A) /T

=-2.303 log(80/100) / 10

=0.0223 .

Therefore k = 0.0223 min^ -1