Question

A first order reaction is found to have a rate constant k=5.5 *10raised to power -14 s-1 find the half life of the reaction

Answer 1

half life time of first order

Answer 2

Answer : The half life of the reaction is, $1.26\times 10^{13}s$

Solution : Given,

Rate constant = $5.5\times 10^{-14}s^{-1}$

Relation between the rate constant and the half life of the reaction is,

$t_{1/2}=\frac{0.693}{k}$

where,

$t_{1/2}$ = half life of the reaction

k = rate constant of the reaction

Now put all the given values in the above relation, we get

$t_{1/2}=\frac{0.693}{5.5\times 10^{-14}s^{-1}}$

$t_{1/2}=1.26\times 10^{13}s$

Therefore, the half life of the reaction is, $1.26\times 10^{13}s$