a first order reaction of 40% completed in 10 minutes . how long will it take to complete 30% of reaction
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1. For the first order reaction k Assume, a = 100 %, x = 40%, t = 50 minutes Therefore, a – x = 100 – 40 = 60 k = (2.303/50) log (100/60) k = 0.010216 min-1 Hence the value of the rate constant is 0.010216 min-1 2. t = ?, when x = 8O% Therefore, a – x = 100 – 80 = 20 From above, k = 0.0102 16 min-1 t = (2.303 / 0.010216) log (100 / 20) t = 157.58 min The time at which the reaction will be 80% complete is 157.58 min.Read more on Sarthaks.com - https://www.sarthaks.com/885154/first-order-reaction-complete-minutes-calculate-value-constant-will-reaction-complete
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Answer:
40/100 in 10 minutes
10/100 in 2.5 minutes
so 7.5 minutes is required
Explanation:
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