Question

a first order reaction take 8 horse for 90% completion calculate the time required for 80% completion​

Answer 1

Answer:

$\large\rm { t = \frac {2.303}{k} \ log \ \frac {9}{9-x} }$

$\large\rm { 8 = \frac {2.303}{k} \ × log ( \frac {100}{100-90} ) .......(1) }$

$\large\rm { t = \frac {2.303}{k} × log ( \frac {100}{100-80} ) ......(2) }$

$\large\rm { \frac {8}{t} = \frac { log \frac {100}{10}}{log \frac {100}{20}} = \frac { log \ 10}{ log \ 5}}$

$\large\rm { \frac {8}{t} = \frac {1}{7}}$

$\large\rm { t = \ 7 \times 8 = 56 \ Hours }$