Question

a first order reaction takes 40 minutes for 30% of decomposition calculate t1?2 for this reaction. (given log 1.428= 0.1548)

Answer 1

Answer:

After 40min rest compound is 70%, applying this first order kinetics

k = 2.303/t log (100/70) or k = 2.303/40

log(1.428) ,As given log1.428=.1548

So k = 2.303/40 ×.1548, or k=8.9×10

−3

Now-

k = .693/t half or t half = .693/9×10–³ or t half

=77min.