A first order reaction which is 30% complete in 30 min has a half life period of
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\[k=\frac{2.303}{t}\log \frac{a}{a-x}\] \[\frac{0.693}{T}=\frac{2.303}{t}\log \frac{100}{100-30}\] \[\therefore \,\,T=58.2\]min.
ANSWER IS 58.2 MIN.
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___***¥0ur Answer is here***____⤵⤵⤵
\[k=\frac{2.303}{t}\log \frac{a}{a-x}\] \[\frac{0.693}{T}=\frac{2.303}{t}\log \frac{100}{100-30}\] \[\therefore \,\,T=58.2\]min.
ANSWER IS 58.2 MIN.
Hope this information will clear your doubts about the topic.
If you have any more doubts just ask here on the brainly and our experts will try to help you out as soon as possible.
^_^
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