A first order reaction which is 30% complete in 30 minutes has a half life period of
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Answered by
18
Hey Dear,
● Answer -
T = 58.28 min
● Explanation -
As we know,
t = (1/k) ln(a / a-x)
Here,
30 = (1/k) ln(100 / 100-30)
k = ln(10/7) / 30
k = 0.3567 / 30
k = 0.01189
Half life of the reaction is calculated as -
T = 0.693 / k
T = 0.693 / 0.01189
T = 58.28 min
Hence, half life of the reaction is 58.28 min.
Hope this helped you.
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Answer:
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