Question

A first seder reaction is 15% complete in
20 minutes. How long will it take to
complete 60%?​

Answer 1

Answer:

HI MATE !

$\large{ \red{ \underline{ \mathbb{QUESTION :-}}}}$

A first order reaction is 15% complete in

20 minutes. How long will it take to

complete 60%?

$\large{ \purple{ \underline{ \mathbb{ANSWER :-}}}}$

The integrated rate equation for first order is:

-ln(1-X) = KT

X is the conversion.

K is the rate constant.

T is the time .

Substituting the first condition of X=.15 and T=20 min we get K = 8.12 * 10^-3 min ^-1

Substituting the second condition of X= 60 and K (known from previous step) ,because rate constant remains the same.

We get T= 112.84= 113 min

Time for 60 ℅ conversion is 113 min.

Hope my answer helps you Dear.. ❤️

BRAINLIEST ᑭLՏ.. ✅

:-)

Answer 2

The integrated rate equation for first order is:

-ln(1-X) = KT

X is the conversion.

K is the rate constant.

T is the time .

Substituting the first condition of X=.15 and T=20 min we get K = 8.12 * 10^-3 min ^-1

Substituting the second condition of X= 60 and K (known from previous step) ,because rate constant remains the same.

We get T= 112.84= 113 min

Time for 60 ℅ conversion is 113 min.