Question

A fish 40 cm beneath the surface of pond sees a bird directly over head. If the bird is
actually 15 cm above the water surface, the same appears to be seen by the fish above
the water surface at a height of

Answer 1

Answer:

the fish is under water…

so if the real height of bitd is h m above the surface the fish will see it at h’

such that

real height/apparent height = refractive index of water =3/4 = g(mu)a

h/ h’ = 3/4 so the speed dh/dt / dh’/dt = 3/4 ,

v(bird)/ v’(as seen by fish) = 3/4

so the velocity

seen by fish =dh’/dt = (4/3 ) * dh/dt

= (4/3 )* 6 m/s = 8 m/s

Explanation:

Answer 2

Answer:

A fish 40 cm beneath the surface of pond sees a bird directly over head. If the bird is

actually 15 cm above the water surface, the same appears to be seen by the fish above

the water surface at a height of