A fish in a lake is at a 6.3 m distance from the edge of the lake. If it is just able to see a tree on the edge of the lake, its depth in the lake is _______ m. Refractive index of the water is 1.33.(A) 6.30 (B) 5.52 (C) 7.5 (D) 1.55
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Thus the depth in the lake is 5.52 m
Option (B) is correct.
Explanation:
Sin θc = 1 / μ
tan θ = 6.3 / h
Sin θc = 1 / 1.33 ( 100 / 133)
tan θ = ln / √ 133^2 - 100^2 6.3 / h
h = 6.3√ 133^2 - 100^2 / 100
h = 6.3 x 87.68 / 100
h = 5.52 m
Thus the depth in the lake is 5.52 m
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