Question

A fish in an aquarium approaches the left wall at a rate of 3 m s-1

observes a fly approaching it at

8 ms-1

If the refractive index of water is ( 4/3), find the actual velocity of the fly.
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Answer 1

The velocity of the fly is 3.75 m/s

Explanation:

We are given that:

The distance of the fly from the wall to the aquarium = μx

Here "x" is the actual distance.

Now the velocity will be;

Solution:

v = d (μx) / dt

The velocity of the fly observed by the fish = 8 m/s

v (fish ) + v(fly) = 8 m/s  

Velocity of fly = 5 x 3/4 = 3.75 m/s

Thus the velocity of the fly is 3.75 m/s

Answer 2

Answer:

3.75 m/s

Given ;

The distance of the fly from the wall to the aquarium = μx

Here "x" is the actual distance.

Now the velocity will be;

v = d (μx) / dt

The velocity of the fly observed by the fish = 8 m/s

v (fish ) + v(fly) = 8 m/s  

Velocity of fly = 5 x 3/4 = 3.75 m/s

Thus the velocity of the fly is 3.75 m/s

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