Question

A fish in water (refractive index n) looks at a bird vertically above in the air . If y is the height of the bird and x is the depth of the fish from the surface , then the distance of the bird as estimated by the fish is
A) x + y(1+1/n)
B) y + x(1-1/n)
C) x + y(1-1/n)
D) x + ny

Answer 1

If the object is in rarer medium and the fish is looked from the denser medium, we know Normal shift d = (n-1) h, where h represents the real depth.

Again I the question it is given that h =y.

Therefore apparent depth or the height of the bird from the water surface is y + (n-1)y = NY.

Hence the total distance is X+ny.

The option D is correct.

Answer 2

Answer:

x+by is the apparent depth