Question

A fish is at a depth of 12cm in water is viewed by observer on the bank of lake. To what height image
of fish is raised ...(u°=4/3)​

Answer 1

Answer:

fish is at a depth of 12cm in water is viewed by observer on the bank of lake. To what height image

of fish is raised ...(u°=4/3)fish is at a depth of 12cm in water is viewed by observer on the bank of lake. To what height image

of fish is raised ...(u°=4/3).

Answer 2

Question:

A fish is at a depth of 12 cm in water is viewed by observer on the bank of lake. To what height image  of fish is raised? (μ = 4/3)

Solution:

Real Depth of fish which is observed by the observer, $D_{r}$ = 12 cm            

Refractive index of water, $\mu_{w}$ = 4/3

Apparent Depth or place where fish image will form, $D_{a}$ = x cm  [Let it be x]

$Refractive \ Index = \frac{Real \ Depth}{Apparent \ Depth}$

$\mu_{w} = \frac{D_{r} }{D_{a} }$

$\frac{4}{3} = \frac{12}{D_{a} }$

$D_{a} = \frac{12 * 3}{ 4}$

$D_{a} = 9 \ cm$

The apparent depth or the place where fish will appear will be at 9 cm.

But, we have to find out how much is the image of fish raised from the real depth,

Image raised = Real Depth - Apparent Depth = 12 - 9 = 3 cm

The height at which image of fish is raised is 3 cm.