Question

A fish is in the lake is at a 6. 3m distance from the edge of the lake.if it is just able to see a tree on the edge of lake is. m.refractive index of water is 1.33

Answer 1

Answer:8.379m

Explanation: Refractive index=. Real depth/ apparent depth

Real depth= Refractive index* apparent depth

6.3*1.33= 8.379m

Answer 2

Thus the depth of the lake is 5.55 m

Explanation:  

Refractive index of water = 1.33  

θ = sin^-1 ( 1 / μ)  

sin^-1 ( 3/4) = 48.54  

tan ( 90° - C) = h / 6.3

cot C = h / 6.3

0.8819 = h / 6.3

h = 0.8819 x 6.3  

h = 5.55 m

Thus the depth of the lake is 5.55 m