a fish is swimming up with a speed of 12 cm/s in water [μ = 4/3]. the speed of the fish as seen by the person outside is
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Explanation:
Let the refractive index of water be n =4/3
n=(real depth)/(apparent depth)
Therefore
n(apparent depth)=(real depth)
n(d)=d'---(1)
Differentiating (1) wrt time,
n(apparent velocity) =actual velocity
n(v')=v
Where v' is the velocity of fish according to man
=>v'=(3/4)(v)
=>v'=12•3/4 =9cm/sec
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