Question

A fish lays brown eggs or white eggs and it likes to lay them in a
certain pattern. Each brown egg is surrounded by six white eggs.
Here there are 3 brown eggs and 14 white eggs.
(a) How many eggs does it lay altogether if it lays 200 brown eggs?
(b) How many eggs does it lay altogether if it lays n brown eggs?​

Answer 1

a) 802

b) 6n-2(n-1)

Hope it helps!

Answer 2

Answer:

a)Here for the first brown egg it need 6 white eggs surrounded it. But from the second egg onwards the 6 eggs surrounding it will be the repetitive of the previous one so we have to only consider 4 eggs

ie. 200 = 199 + 1

for 200 brown eggs = 199*4 + 1*6

= 802

b) consider it as an arithmetic expression:

ie first brown egg is covered by 6 white eggs and others with a common difference 4

ie the sequence is 6,10,14,18,22..

nth term = a1 + (n-1)d

a1 =6

d =4

an = 6 + (n-1)4

an = 4n+2