A fish looking upwards through the water seeing the outside world contained in a circular horizon. if the refractive index of water is 4/3 and the fish is 12 cm below the surface,the radius of this circle in cm is
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Using snell's law
sin(i) sin(r)=μ2 μ1
r=90° ;sin(r) =1 & μ2=1
sini=143=34
tani=3√7
; radius=36√7 better written as 36√77
Hope it will help you
sin(i) sin(r)=μ2 μ1
r=90° ;sin(r) =1 & μ2=1
sini=143=34
tani=3√7
; radius=36√7 better written as 36√77
Hope it will help you
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