A fish seems to be 4cm below water surface.If the refractive index of water is 1.33 then find the actual position of fish from water surface.
Answers
Answered by
3
The fraction is...
\frac{5(x - 3)}{6} - x = 1 - \frac{x}{9}
6
5(x−3)
−x=1−
9
x
Solve the bracket...
\frac{5x - 15}{6} - x = 1 - \frac{x}{9}
6
5x−15
−x=1−
9
x
Take the LCM of denominators...
\frac{5x - 15 - 6x}{6} = \frac{9 - x}{9}
6
5x−15−6x
=
9
9−x
Reduce the denominators to simplest forms and solve the required in numerator...
\frac{ - x - 15}{2} = \frac{9 - x}{3}
2
−x−15
=
3
9−x
By Cross Multiplication...
3( - x - 15) = 2(9 - x)3(−x−15)=2(9−x)
- 3x - 45 = 18 - 2x−3x−45=18−2x
- 3x + 2x = 18 + 45−3x+2x=18+45
- x = 63−x=63
The answer is...
x = - 63x=−63
pls mark as brainliest
also give thanks
Answered by
1
Answer:
4+1.33
Explanation:
4-1.33 ju na ya
Similar questions