Question

A fish swimming at a constant speed of 0.5 m/s suddenly notices a shark appear behind it. Five seconds later, the fish is swimming in the same direction at a speed of 2.5 m/s. Calculate the fish’s acceleration?

Answer 1

Explanation:

because the formula is

a= v- v'/ t

; a = acceleration

v= final speed

v'= starting speed

t= time

Answer 2

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A fish swimming at a constant speed of 0.5 m/s suddenly notices a shark appear behind it. 5 seconds later, the fish swimming in the same direction at a speed of 2.5 m/s. Calculate the fish’s acceleration. *

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Given : A fish swimming at a constant speed of 0.5 m/s [ as , Initial Velocity ( u ) ] , After noticing the shark fish's speed is 2.5 m/s [ as , Final Velocity ( v ) ] & Time taken is 5 seconds [ as , Time ( t ) ]

Exigency To Find : The Acceleration of fish ?

⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀

⠀⠀⠀⠀Given that ,

⠀⠀⠀⠀⠀⠀⠀⠀▪︎⠀⠀The initial velocity ( u ) of fish is 0.5 m/s .

⠀⠀⠀⠀⠀⠀⠀⠀▪︎⠀⠀The final velocity ( v ) of fish is 2.5 m/s

⠀⠀⠀⠀⠀⠀⠀⠀▪︎⠀⠀Total Time taken ( t ) is 5 seconds

Lets Finding  Acceleration  of fish! :

$\begin{gathered}\dag\:\:\pmb{ As,\:We\:know\:that\::}\\\\ \qquad \bigstar \:\: \bf Acceleration \: : \: \sf The \: rate \:of \: of \: change \:of\: velocity\:is \:known \: as \: Acceleration \:. \:\\\\ \qquad\maltese\:\:\bf Formula \:for \: Acceleration\:: \\\end{gathered}$

$\begin{gathered}\qquad \dag\:\:\bigg\lgroup \pmb{\bf{\;\: Acceleration\:(a)\:=\:\dfrac{ \:\: v \:\:- \:\:u\:\:}{t}\:\: }}\bigg\rgroup \\\\\end{gathered}$

⠀⠀⠀⠀Here , u is the Initial velocity, v is the final velocity & t is the time taken .

$\begin{gathered}\qquad \dashrightarrow \sf Acceleration\:(a)\:=\:\dfrac{ \:\: v \:\:- \:\:u\:\:}{t}\qquad \:\\\\\end{gathered}$

$\begin{gathered}\underline {\boldsymbol{\star\:Now \: By \: Substituting \: the \: known \: Values \::}}\\\end{gathered}$

$\begin{gathered}\qquad \dashrightarrow \sf Acceleration\:(a)\:=\:\dfrac{ \:\: v \:\:- \:\:u\:\:}{t}\qquad \:\\\\\end{gathered}$

$\begin{gathered}\qquad \dashrightarrow \sf Acceleration\:(a)\:=\:\dfrac{ \:\: 2.5 \:\:- \:\:0.5\:\:}{5}\qquad \:\\\\\end{gathered}$

$\begin{gathered}\qquad \dashrightarrow \sf Acceleration\:(a)\:=\:\dfrac{ \:\: 2\:\:}{5}\qquad \:\\\\\end{gathered}$

$\begin{gathered}\qquad \dashrightarrow \sf Acceleration\:(a)\:=\:\cancel {\dfrac{ \:\: 2\:\:}{5}}\qquad \:\\\\\end{gathered}$

$\begin{gathered}\qquad \dashrightarrow \sf Acceleration\:(a)\:=\:0.4 \:\qquad \:\\\\\end{gathered}$

$\begin{gathered}\qquad \therefore \pmb{\underline{\purple{\frak{ \:Acceleration\:(a)\:=\:0.4 \:m/s^2 }}} }\:\:\bigstar \\\end{gathered}$

$\begin{gathered}\therefore \:\underline { \sf Hence , \:\: The \:Acceleration \:of\:fish\:is \: \bf 0.4 \: m/s^2 \:}.\\\\\end{gathered}$