A fish tank in the shape of a cuboid has length, breadth and height of 60 cm, 40 cm and 80 cm respectively and is filled with water. the base of the tank is tilted by 45 degree along the breadth and the water coming out from the tank is collected in an empty vessel. The volume of water collected in the empty vessel is 32 liters. What was the height of the water that was initially there in the cuboid tank? [thickness is negligible]
Answers
Answer:
After the tank is tilted, the volume of empty space in the tank equals 1/2*60*60*40 = 72 litres.
After the tank is tilted, the volume of empty space in the tank equals 1/2*60*60*40 = 72 litres.This includes 32 litres of water which was collected.
After the tank is tilted, the volume of empty space in the tank equals 1/2*60*60*40 = 72 litres.This includes 32 litres of water which was collected.So, the volume of the empty space before was 40 litres.
After the tank is tilted, the volume of empty space in the tank equals 1/2*60*60*40 = 72 litres.This includes 32 litres of water which was collected.So, the volume of the empty space before was 40 litres.Hence, the height of the empty space was 40*1000/(40*60) = 16.66 cm
After the tank is tilted, the volume of empty space in the tank equals 1/2*60*60*40 = 72 litres.This includes 32 litres of water which was collected.So, the volume of the empty space before was 40 litres.Hence, the height of the empty space was 40*1000/(40*60) = 16.66 cmHence, the height of water originally was 80-16.66 = 63.33 cm