A fish under water observes a freely falling stone. If the refractive index of water is 4/3 then what is the apparent acceleration observed by the fish under water?
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Answers
Answer:
The apparent position of stone as observed by the fish will always be 4/3 times its actual position.
so the velocity and acceleration will also be observed 4/3 times its actual position.
i.e. it will be 4/3*9.81 =13.1m/s
The position of object(outside water) observed by the person( inside water) is always 1.33 times more.
lets say when position of stone is d1 the apparant position of stone as observed by person under water will be 1.33d1.
and the next position of stone is d2 the apparant position will be 1.33d2.
distance travelled by the stone as observed by fish under water will be 1.33(d2-d1), i.e. 1.33 times more.
This gives us clear idea that the velocity will also be 1.33 times in this case.
and same goes with acceleration.
Thus aparant accelearation will be 1.33 times the real acceleration
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