A fisherman in a boat catches a huge fish with a rod and starts to pull it in. The fishstruggles for a while and then becomes still when it is at a distance of 200 m from theboat. During this operation, the boat (initially at rest) moves 25 m in the direction of thefish. If the mass of the boat is 5000 kg, calculate the mass of the fish. Assume that waterexerts no friction.
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On the surface of water, there is no horizontal external force on the system of fish and boat along with the fisherman and the fishing rod.
In the question, the 200m is the distance the fish moved in during the struggle. I think there is a mistake in the question.
The center of mass remains at the same position, as there is no external force acting them. Let the mass of the fish be M kg. Let the initial position of the center of mass be 0.
So M * 200 = 5000 * 25
M = 625 Kg
Mass of the fish = 625 kg.
In the question, the 200m is the distance the fish moved in during the struggle. I think there is a mistake in the question.
The center of mass remains at the same position, as there is no external force acting them. Let the mass of the fish be M kg. Let the initial position of the center of mass be 0.
So M * 200 = 5000 * 25
M = 625 Kg
Mass of the fish = 625 kg.
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