Math, asked by Shubhambattan1193, 11 months ago

A fit is specified as 25h8/e8. The tolerance value for a nominal diameter of 25 mm in it8 is 33 microns and fundamental deviation for the shaft is †40 microns. The maximum clearance of the fit in microns is (a) â€7 (b) 7 (c) 73 (d) 106

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Answered by satvika90
0
sorry I don't know...?? any one answers this question
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